-7x-5=(1-x)^2

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Solution for -7x-5=(1-x)^2 equation: 



-7x-5=(1-x)^2

We move all terms to the left:

-7x-5-((1-x)^2)=0

We add all the numbers together, and all the variables

-7x-((-1x+1)^2)-5=0



We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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We calculate terms in parentheses: -((-1x+1)^2), so:

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